5.5: Dividing Polynomials (2024)

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    Learning Objectives

    By the end of this section, you will be able to:

    • Divide monomials
    • Divide a polynomial by a monomial
    • Dividepolynomials using long division
    • Dividepolynomials using synthetic division
    • Dividepolynomial functions
    • Use the remainder and factor theorems

    Before you get started, take this readiness quiz.

    1. Add: \(\dfrac{3}{d}+\dfrac{x}{d}\).
      If you missed this problem, review [link].
    2. Simplify: \(\dfrac{30xy}{35xy}\).
      If you missed this problem, review [link].
    3. Combine like terms: \(8a^2+12a+1+3a^2−5a+4\).
      If you missed this problem, review [link].

    Dividing Monomials

    We are now familiar with all the properties of exponents and used them to multiply polynomials. Next, we’ll use these properties to divide monomials and polynomials.

    Example \(\PageIndex{1}\)

    Find the quotient: \(54a^2b^3÷ (−6ab^5)\).

    Solution

    When we divide monomials with more than one variable, we write one fraction for each variable.

    \(\begin{array} {ll} {} &{54a^2b^3÷(−6ab^5)} \\[5pt] {\text{Rewrite as a fraction.}} &{\dfrac{54a^2b^3}{−6ab^5}} \\[5pt] {\text{Use fraction multiplication.}} &{\dfrac{54}{−6}·\dfrac{a^2}{a}·\dfrac{b^3}{b^5}} \\[5pt] {\text{Simplify and use the Quotient Property.}} &{−9·a·\dfrac{1}{b^2}} \\[5pt] {\text{Multiply.}} &{−\dfrac{9a}{b^2}} \end{array}\)

    Try It! \(\PageIndex{1}\)

    Find the quotient: \(−72a^7b^3÷(8a^{12}b^4)\).

    Answer

    \(−\dfrac{9}{a^5b}\)

    Try It! \(\PageIndex{2}\)

    Find the quotient: \(−63c^8d^3÷(7c^{12}d^2)\).

    Answer

    \(\dfrac{−9d}{c^4}\)

    Once you become familiar with the process and have practiced it step by step several times, you may be able to simplify a fraction in one step.

    Example \(\PageIndex{2}\)

    Find the quotient: \(\dfrac{14x^7y^{12}}{21x^{11}y^6}\).

    Solution

    Be very careful to simplify \(\dfrac{14}{21}\) by dividing out a common factor, and to simplify the variables by subtracting their exponents.

    \(\begin{array} {ll} {} &{\dfrac{14x^7y^{12}}{21x^{11}y^6}} \\ {\text{Simplify and use the Quotient Property.}} &{\dfrac{2y^6}{3x^4}} \\ \end{array}\)

    Try It! \(\PageIndex{4}\)

    Find the quotient: \(\dfrac{30m^5n^{11}}{48m^{10}n^{14}}\).

    Answer

    \(\dfrac{5}{8m^5n^3}\)

    Divide a Polynomial by a Monomial

    Now that we know how to divide a monomial by a monomial, the next procedure is to divide a polynomial of two or more terms by a monomial. The method we’ll use to divide a polynomial by a monomial is based on the properties of fraction addition. So we’ll start with an example to review fraction addition. The sum \(\dfrac{y}{5}+\dfrac{2}{5}\) simplifies to \(\dfrac{y+2}{5}\). Now we will do this in reverse to split a single fraction into separate fractions. For example, \(\dfrac{y+2}{5}\) can be written \(\dfrac{y}{5}+\dfrac{2}{5}\).

    This is the “reverse” of fraction addition and it states that if a, b, and c are numbers where \(c\neq 0\), then \(\dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}\). We will use this to divide polynomials by monomials.

    definition: DIVISION OF A POLYNOMIAL BY A MONOMIAL

    To divide a polynomial by a monomial, divide each term of the polynomial by the monomial.

    Example \(\PageIndex{3}\)

    Find the quotient: \((18x^3y−36xy^2)÷(−3xy)\).

    Solution

    \(\begin{array} {ll} {} &{(18x^3y−36xy^2)÷(−3xy)} \\[5pt] {\text{Rewrite as a fraction.}} &{\dfrac{18x^3y−36xy^2}{−3xy}} \\[5pt] {\text{Divide each term by the divisor. Be careful with the signs!}} &{\dfrac{18x^3y}{−3xy}−\dfrac{36xy^2}{−3xy}} \\[5pt] {\text{Simplify.}} &{−6x^2+12y} \end{array}\)

    Try It! \(\PageIndex{5}\)

    Find the quotient: \((32a^2b−16ab^2)÷(−8ab)\).

    Answer

    \(−4a+2b\)

    Try It! \(\PageIndex{6}\)

    Find the quotient: \((−48a^8b^4−36a^6b^5)÷(−6a^3b^3)\).

    Answer

    \(8a^5b+6a^3b^2\)

    Divide Polynomials Using Long Division

    Divide a polynomial by a binomial, we follow a procedure very similar to long division of numbers. So let’s look carefully the steps we take when we divide a 3-digit number, 875, by a 2-digit number, 25.

    5.5: Dividing Polynomials (2)

    We check division by multiplying the quotient by the divisor. If we did the division correctly, the product should equal the dividend.

    \[\begin{array} {l} {35·25} \\ {875\checkmark} \\ \nonumber \end{array}\]

    Now we will divide a trinomial by a binomial. As you read through the example, notice how similar the steps are to the numerical example above.

    Example \(\PageIndex{4}\)

    Find the quotient: \((x^2+9x+20)÷(x+5)\).

    Solution

    \(\require{enclose}\) \(\qquad (x^2+9x+20) \div (x+5)\)
    Write it as a long division problem.
    Be sure the dividend is in standard form.

    \(\qquad x+5\enclose{longdiv}{ x^2+9x+20\phantom{0}} \)

    Divide \(x^2\) by \(x\). It may help to ask yourself, “What do I need
    to multiply \(x\) by to get \(x^2\)?”

    \(\qquad \begin{array}{r} {\color{red}x}\hspace{2.3em}\\[-3pt] {\color{red}x}+5\enclose{longdiv}{ {\color{red}x^2}+9x+20\phantom{0}}\end{array}\)

    Put the answer, \(x\), in the quotient over the \(x\) term.
    Multiply \(x\) times \(x+5\). Line up the like terms under the dividend.

    \(\qquad \begin{array}{r}x\hspace{2.3em}\\[-3pt] x+5\enclose{longdiv}{x^2+9x+20\phantom{0}}\\[-3pt] \underline{\color{red}x^2+5x}\hspace{2.4em}\end{array}\)

    Subtract \(x^2+5x\) from \(x^2+9x\).
    You may find it easier to change the signs and then add.
    Then bring down the last term, \(20.\)

    \(\qquad \begin{array}{r}x\hspace{2.3em}\\[-3pt] x+5\enclose{longdiv}{x^2+\phantom{00}9x+20\phantom{0}}\\[-3pt] \underline{{\color{red}-}x^2+({\color{red}-}5x)}\hspace{2.1em}\\[-3pt] {\color{red}4x+20}\hspace{0.5em}\end{array}\)


    Divide \(4x\) by \(x\). It may help to ask yourself, “What do I
    need to multiply \(x\) by to get \(4x\)?”
    Put the answer, \(4\), in the quotient over the constant term.

    \(\qquad \begin{array}{r}x+\phantom{0}{\color{red}4}\hspace{.5em}\\[-3pt] {\color{red}x}+5\enclose{longdiv}{x^2+\phantom{00}9x+20\phantom{0}}\\[-3pt] \underline{{\color{red}-}x^2+({\color{red}-}5x)}\hspace{2.1em}\\[-3pt] {\color{red}4x}+20\hspace{0.5em}\end{array}\)

    Multiply 4 times \(x+5\).

    \(\qquad \begin{array}{r}x+\phantom{0}4\hspace{.5em}\\[-3pt] x+5\enclose{longdiv}{x^2+\phantom{00}9x+20\phantom{0}}\\[-3pt] \underline{{\color{red}-}x^2+({\color{red}-}5x)}\hspace{2.1em}\\[-3pt] 4x+20\hspace{0.5em}\\[-3pt] \underline{\color{red}4x+20}\hspace{.5em} \end{array}\)

    Subtract \(4x+20\) from \(4x+20\).

    \(\qquad \begin{array}{r}x+\phantom{0}4\hspace{.5em}\\[-3pt] x+5\enclose{longdiv}{x^2+\phantom{00}9x+20\phantom{0}}\\[-3pt] \underline{{\color{red}-}x^2+({\color{red}-}5x)}\hspace{2.1em}\\[-3pt] 4x+20\hspace{.5em}\\[-3pt] \underline{{\color{red}-}4x+({\color{red}-}20)}\\[-3pt] 0\hspace{.33em}\end{array}\)

    Check:

    \(\begin{array} {ll} {\text{Multiply the quotient by the divisor.}} &{(x+4)(x+5)} \\ {\text{You should get the dividend.}} &{x^2+9x+20\checkmark}\\ \end{array}\)

    Try It! \(\PageIndex{7}\)

    Find the quotient: \((y^2+10y+21)÷(y+3)\).

    Answer

    \(y+7\)

    Try It! \(\PageIndex{8}\)

    Find the quotient: \((m^2+9m+20)÷(m+4)\).

    Answer

    \(m+5\)

    When we divided 875 by 25, we had no remainder. But sometimes division of numbers does leave a remainder. The same is true when we divide polynomials. In the next example, we’ll have a division that leaves a remainder. We write the remainder as a fraction with the divisor as the denominator.

    Look back at the dividends in previous examples. The terms were written in descending order of degrees, and there were no missing degrees. The dividend in this example will be \(x^4−x^2+5x−6\). It is missing an \(x^3\) term. We will add in \(0x^3\) as a placeholder.

    Example \(\PageIndex{5}\)

    Find the quotient: \((x^4−x^2+5x−6)÷(x+2)\).

    Solution

    Notice that there is no \(x^3\) term in the dividend. We will add \(0x^3\) as a placeholder.

    5.5: Dividing Polynomials (3)
    Write it as a long division problem. Be sure the dividend is in standard form with placeholders for missing terms. 5.5: Dividing Polynomials (4)
    Divide \(x^4\) by \(x\).
    Put the answer, \(x^3\), in the quotient over the \(x^3\) term.
    Multiply \(x^3\) times \(x+2\). Line up the like terms.
    Subtract and then bring down the next term.
    5.5: Dividing Polynomials (5)
    Divide \(−2x^3\) by \(x\).
    Put the answer, \(−2x^2\), in the quotient over the \(x^2\) term.
    Multiply \(−2x^2\) times \(x+1\). Line up the like terms
    Subtract and bring down the next term.
    5.5: Dividing Polynomials (6)
    Divide \(3x^2\) by \(x\).
    Put the answer, \(3x\), in the quotient over the \(x\) term.
    Multiply \(3x\) times \(x+1\). Line up the like terms.
    Subtract and bring down the next term.
    5.5: Dividing Polynomials (7)
    Divide \(−x\) by \(x\).
    Put the answer, \(−1\), in the quotient over the constant term.
    Multiply \(−1\) times \(x+1\). Line up the like terms.
    Change the signs, add.

    Write the remainder as a fraction with the divisor as the denominator.

    5.5: Dividing Polynomials (8)
    To check, multiply \((x+2)(x^3−2x^2+3x−1−4x+2)\).
    The result should be \(x^4−x^2+5x−6\).
    Try It! \(\PageIndex{9}\)

    Find the quotient: \((x^4−7x^2+7x+6)÷(x+3)\).

    Answer

    \(x^3−3x^2+2x+1+3x+3\)

    Try It! \(\PageIndex{10}\)

    Find the quotient: \((x^4−11x^2−7x−6)÷(x+3)\).

    Answer

    \(x^3−3x^2−2x−1−3x+3\)

    In the next example, we will divide by \(2a−3\). As we divide, we will have to consider the constants as well as the variables.

    Example \(\PageIndex{6}\)

    Find the quotient: \((8a^3+27)÷(2a+3)\).

    Solution

    This time we will show the division all in one step. We need to add two placeholders in order to divide.

    5.5: Dividing Polynomials (9)
    5.5: Dividing Polynomials (10)

    To check, multiply \((2a+3)(4a^2−6a+9)\).

    The result should be \(8a^3+27\).

    Try It! \(\PageIndex{11}\)

    Find the quotient: \((x^3−64)÷(x−4)\).

    Answer

    \(x^2+4x+16\)

    Try It! \(\PageIndex{12}\)

    Find the quotient: \((125x^3−8)÷(5x−2)\).

    Answer

    \(25x^2+10x+4\)

    Divide Polynomials using Synthetic Division

    As we have mentioned before, mathematicians like to find patterns to make their work easier. Since long division can be tedious, let’s look back at the long division we did in Example and look for some patterns. We will use this as a basis for what is called synthetic division. The same problem in the synthetic division format is shown next.

    5.5: Dividing Polynomials (11)

    Synthetic division basically just removes unnecessary repeated variables and numbers. Here all the \(x\) and \(x^2\) are removed. as well as the \(−x^2\) and \(−4x\) as they are opposite the term above.

    • The first row of the synthetic division is the coefficients of the dividend. The \(−5\) is the opposite of the 5 in the divisor.
    • The second row of the synthetic division are the numbers shown in red in the division problem.
    • The third row of the synthetic division are the numbers shown in blue in the division problem.

    Notice the quotient and remainder are shown in the third row.

    \[\text{Synthetic division only works when the divisor is of the form }x−c. \nonumber \]

    The following example will explain the process.

    Example \(\PageIndex{7}\)

    Use synthetic division to find the quotient and remainder when \(2x^3+3x^2+x+8\) is divided by \(x+2\).

    Solution

    Write the dividend with decreasing powers of \(x\). 5.5: Dividing Polynomials (12)
    Write the coefficients of the terms as the first
    row of the synthetic division.
    5.5: Dividing Polynomials (13)
    Write the divisor as \(x−c\) and place c
    in the synthetic division in the divisor box.
    5.5: Dividing Polynomials (14)
    Bring down the first coefficient to the third row. 5.5: Dividing Polynomials (15)
    Multiply that coefficient by the divisor and place the
    result in the second row under the second coefficient.
    5.5: Dividing Polynomials (16)
    Add the second column, putting the result in the third row. 5.5: Dividing Polynomials (17)
    Multiply that result by the divisor and place the
    result in the second row under the third coefficient.
    5.5: Dividing Polynomials (18)
    Add the third column, putting the result in the third row. 5.5: Dividing Polynomials (19)
    Multiply that result by the divisor and place the
    result in the third row under the third coefficient.
    5.5: Dividing Polynomials (20)
    Add the final column, putting the result in the third row. 5.5: Dividing Polynomials (21)
    The quotient is \(2x^2−1x+3\) and the remainder is 2.

    The division is complete. The numbers in the third row give us the result. The \(2\space\space\space−1\space\space\space3\) are the coefficients of the quotient. The quotient is \(2x^2−1x+3\). The 2 in the box in the third row is the remainder.

    Check:

    \(\begin{align} (\text{quotient})(\text{divisor}) + \text{remainder} &= \text{dividend} \nonumber\\ (2x^2−1x+3)(x+2)+2 &\overset{?}{=} 2x^3+3x^2+x+8 \nonumber\\ 2x^3−x^2+3x+4x^2−2x+6+2 &\overset{?}{=} 2x^3+3x^2+x+8 \nonumber\\ 2x^3+3x^2+x+8 &= 2x^3+3x^2+x+8\checkmark \nonumber \end{align} \)

    Try It! \(\PageIndex{13}\)

    Use synthetic division to find the quotient and remainder when \(3x^3+10x^2+6x−2\) is divided by \(x+2\).

    Answer

    \(3x^2+4x−2;\space 2\)

    Try It! \(\PageIndex{14}\)

    Use synthetic division to find the quotient and remainder when \(4x^3+5x^2−5x+3\) is divided by \(x+2\).

    Answer

    \(4x^2−3x+1; 1\)

    In the next example, we will do all the steps together.

    Example \(\PageIndex{8}\)

    Use synthetic division to find the quotient and remainder when \(x^4−16x^2+3x+12\) is divided by \(x+4\).

    Solution

    The polynomial \(x^4−16x^2+3x+12\) has its term in order with descending degree but we notice there is no \(x^3\) term. We will add a 0 as a placeholder for the \(x^3\) term. In \(x−c\) form, the divisor is \(x−(−4)\).

    5.5: Dividing Polynomials (22)

    We divided a \(4^{\text{th}}\) degree polynomial by a \(1^{\text{st}}\) degree polynomial so the quotient will be a \(3^{\text{rd}}\) degree polynomial.

    Reading from the third row, the quotient has the coefficients \(1\space\space\space−4\space\space\space0\space\space\space3\), which is \(x^3−4x^2+3\). The remainder
    is 0.

    Try It! \(\PageIndex{15}\)

    Use synthetic division to find the quotient and remainder when \(x^4−16x^2+5x+20\) is divided by \(x+4\).

    Answer

    \(x^3−4x^2+5;\space 0\)

    Try It! \(\PageIndex{16}\)

    Use synthetic division to find the quotient and remainder when \(x^4−9x^2+2x+6\) is divided by \(x+3\).

    Answer

    \(x^3−3x^2+2;\space 0\)

    Divide Polynomial Functions

    Just as polynomials can be divided, polynomial functions can also be divided.

    definition: DIVISION OF POLYNOMIAL FUNCTIONS

    For functions \(f(x)\) and \(g(x)\), where \(g(x)\neq 0\),

    \[\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)} \nonumber\]

    Example \(\PageIndex{9}\)

    For functions \(f(x)=x^2−5x−14\) and \(g(x)=x+2\), find:

    1. \(\left(\dfrac{f}{g}\right)(x)\)
    2. \(\left(\dfrac{f}{g}\right)(−4)\).

    Solution

    5.5: Dividing Polynomials (23)

    \(\begin{array} {ll} {\text{Substitute for }f(x)\text{ and }g(x).} &{\left(\dfrac{f}{g}\right)(x)=\dfrac{x^2−5x−14}{x+2}} \\[5pt] {\text{Divide the polynomials.}} &{\left(\dfrac{f}{g}\right)(x)=x−7} \end{array} \)

    ⓑ In part ⓐ we found \(\left(\dfrac{f}{g}\right)(x)\) and now are asked to find \(\left(\dfrac{f}{g}\right)(−4)\).

    \(\begin{array} {ll} {} &{\left(\dfrac{f}{g}\right)(x)=x−7} \\[5pt] {\text{To find }\left(\dfrac{f}{g}\right)(−4), \text{ substitute }x=−4.} &{\left(\dfrac{f}{g}\right)(−4)=−4−7} \\[5pt] {} &{\left(\dfrac{f}{g}\right)(−4)=−11} \end{array}\)

    Try It! \(\PageIndex{17}\)

    For functions \(f(x)=x^2−5x−24\) and \(g(x)=x+3\), find:

    1. \(\left(\dfrac{f}{g}\right)(x)\)
    2. \(\left(\dfrac{f}{g}\right)(−3)\).
    Answer a

    \(\left(\dfrac{f}{g}\right)(x)=x−8\)

    Answer b

    \(\left(\dfrac{f}{g}\right)(−3)=−11\)

    Try It! \(\PageIndex{18}\)

    For functions \(f(x)=x2−5x−36\) and \(g(x)=x+4\), find:

    1. \(\left(\dfrac{f}{g}\right)(x)\)
    2. \(\left(\dfrac{f}{g}\right)(−5)\).
    Answer a

    \(\left(\dfrac{f}{g}\right)(x)=x−9\)

    Answer b

    \(\left(\dfrac{f}{g}\right)(x)=x−9\)

    Use the Remainder and Factor Theorem

    Let’s look at the division problems we have just worked that ended up with a remainder. They are summarized in the chart below. If we take the dividend from each division problem and use it to define a function, we get the functions shown in the chart. When the divisor is written as \(x−c\), the value of the function at \(c\), \(f(c)\), is the same as the remainder from the division problem.

    Dividend Divisor \(x−c\) Remainder Function \(f(c)\)
    \(x^4−x^2+5x−6\) \(x−(−2)\) \(−4\) \(f(x)=x^4−x^2+5x−6\) \(−4\)
    \(3x^3−2x^2−10x+8\) \(x−2\) 4 \(f(x)=3x^3−2x^2−10x+8\) 4
    \(x^4−16x^2+3x+15\) \(x−(−4)\) 3 \(f(x)=x^4−16x^2+3x+15\) 3

    To see this more generally, we realize we can check a division problem by multiplying the quotient times the divisor and add the remainder. In function notation we could say, to get the dividend \(f(x)\), we multiply the quotient, \(q(x)\) times the divisor, \(x−c\), and add the remainder, \(r\).

    5.5: Dividing Polynomials (24)
    If we evaluate this at \(c\), we get: 5.5: Dividing Polynomials (25)
    5.5: Dividing Polynomials (26)
    5.5: Dividing Polynomials (27)

    This leads us to the Remainder Theorem.

    Definition: REMAINDER THEOREM

    If the polynomial function \(f(x)\) is divided by \(x−c\), then the remainder is \(f(c)\).

    Example \(\PageIndex{10}\)

    Use the Remainder Theorem to find the remainder when \(f(x)=x^3+3x+19\) is divided by \(x+2\).

    Solution

    To use the Remainder Theorem, we must use the divisor in the \(x−c\) form. We can write the divisor \(x+2\) as \(x−(−2)\). So, our \(c\) is \(−2\).

    To find the remainder, we evaluate \(f(c)\) which is \(f(−2)\).

    5.5: Dividing Polynomials (28)
    To evaluate \(f(−2)\), substitute \(x=−2\). 5.5: Dividing Polynomials (29)
    Simplify. 5.5: Dividing Polynomials (30)
    5.5: Dividing Polynomials (31)
    The remainder is 5 when \(f(x)=x^3+3x+19\) is divided by \(x+2\).
    Check:
    Use synthetic division to check.
    5.5: Dividing Polynomials (32)
    The remainder is 5.
    Try It! \(\PageIndex{19}\)

    Use the Remainder Theorem to find the remainder when \(f(x)=x^3+4x+15\) is divided by \(x+2\).

    Answer

    \(−1\)

    Try It! \(\PageIndex{20}\)

    Use the Remainder Theorem to find the remainder when \(f(x)=x^3−7x+12\) is divided by \(x+3\).

    Answer

    \(6\)

    When we divided \(8a^3+27\) by \(2a+3\) in Example the result was \(4a^2−6a+9\). To check our work, we multiply \(4a2−6a+9\) by \(2a+3\) to get \(8a^3+27\).

    \[(4a^2−6a+9)(2a+3)=8a^3+27 \nonumber \]

    Written this way, we can see that \(4a^2−6a+9\) and \(2a+3\) are factors of \(8a^3+27\). When we did the division, the remainder was zero.

    Whenever a divisor, \(x−c\), divides a polynomial function, \(f(x)\), and resulting in a remainder of zero, we say \(x−c\) is a factor of \(f(x)\).

    The reverse is also true. If \(x−c\) is a factor of \(f(x)\) then \(x−c\) will divide the polynomial function resulting in a remainder of zero.

    We will state this in the Factor Theorem.

    Definition: FACTOR THEOREM

    For any polynomial function \(f(x)\),

    • if \(x−c\) is a factor of \(f(x)\), then \(f(c)=0\)
    • if \(f(c)=0\), then \(x−c\) is a factor of \(f(x)\)
    Example \(\PageIndex{11}\)

    Use the Remainder Theorem to determine if \(x−4\) is a factor of \(f(x)=x^3−64\).

    Solution

    The Factor Theorem tells us that \(x−4\) is a factor of \(f(x)=x^3−64\) if \(f(4)=0\).

    \(\begin{array} {ll} {} &{f(x)=x^3−64} \\[5pt] {\text{To evaluate }f(4) \text{ substitute } x=4.} &{f(4)=4^3−64} \\[5pt] {\text{Simplify.}} &{f(4)=64−64} \\[5pt]{\text{Subtract.}} &{f(4)=0} \end{array}\)

    Since \(f(4)=0, x−4\) is a factor of \(f(x)=x^3−64\).

    Try It! \(\PageIndex{21}\)

    Use the Factor Theorem to determine if \(x−5\) is a factor of \(f(x)=x^3−125\).

    Answer

    yes

    Try It! \(\PageIndex{22}\)

    Use the Factor Theorem to determine if \(x−6\) is a factor of \(f(x)=x^3−216\).

    Answer

    yes

    Access these online resources for additional instruction and practice with dividing polynomials.

    • Dividing a Polynomial by a Binomial
    • Synthetic Division & Remainder Theorem

    Key Concepts

    • Division of a Polynomial by a Monomial
      • To divide a polynomial by a monomial, divide each term of the polynomial by the monomial.
    • Division of Polynomial Functions
      • For functions \(f(x)\) and \(g(x)\), where \(g(x)\neq 0\),
        \(\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\)
    • Remainder Theorem
      • If the polynomial function \(f(x)\) is divided by \(x−c\), then the remainder is \(f(c)\).
    • Factor Theorem: For any polynomial function \(f(x)\),
      • if \(x−c\) is a factor of \(f(x)\), then \(f(c)=0\)
      • if \(f(c)=0\), then \(x−c\) is a factor of \(f(x)\)
    5.5: Dividing Polynomials (2024)

    References

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